# response to https://python-forum.io/Thread-Print-one-line-in-dictionary
data = ( [('ID', '10652'), ('Time', '2018/12/11 02:30')], \
[('ID', '10653'), ('Time', '2018/12/11 03:30')], \
[('ID', '10654'), ('Time', '2018/12/11 04:30')], \
[('ID', '10655'), ('Time', '2018/12/11 05:30')] )
# search all, data may not be sorted
def search_id( id_num ):
ids = str(id_num)
for record in data:
if record[0][1]==ids :
return record
return None
# search to id not higher, if data is sorted by id
# (some records can be missing)
def to_id( id_num ) :
ids = str(id_num);
length = len(data);
i = 0
while i<length :
if data[i][0][1] < ids :
i += 1
elif data[i][0][1] == ids :
return data[i]
else :
return None
print( search_id(10652) ) # [('ID', '10652'), ('Time', '2018/12/11 02:30')]
print( to_id (10653) ) # [('ID', '10653'), ('Time', '2018/12/11 03:30')]
# if you have sorted data without missing records
# you can calculate index of searched row like
zero = int(data[0][0][1])
print( data[10654 -zero] ) # [('ID', '10654'), ('Time', '2018/12/11 04:30')]
#-----------
# you have not dictionary, but if you may change data format
# to dictionary, like
data = { 10652: [('ID', '10652'), ('Time', '2018/12/11 02:30')], \
10653: [('ID', '10653'), ('Time', '2018/12/11 03:30')], \
10654: [('ID', '10654'), ('Time', '2018/12/11 04:30')], \
10655: [('ID', '10655'), ('Time', '2018/12/11 05:30')] }
# you can address records:
print(data[10655] ) # [('ID', '10655'), ('Time', '2018/12/11 05:30')]
